Math, asked by snehalthakre220407, 1 month ago

Find the area of a triangle whose sides are in the ratio of 3 : 5 : 7 and its perimeter is 300 cm. ​

Answers

Answered by BlueberryCupcake
0

Step-by-step explanation:

Let the sides be 3x, 5x and 7x

3x+5x+7x = 15x

Perimeter is sum of all sides

So,

15x = 300

x = 20

Now the sides are equal to:

3x = 3* 20 = 60 cm

5x = 100 cm

7x = 140 cm

Now apply Heron's Formula for the rest of the Q.

Formula of Heron's Formula =

 \sqrt{s(s - a)(s - b)(s - c)}

s = 150

a = 60

b = 100

c = 140

Answered by srisaipoojitha9e2497
1

Step-by-step explanation:

Let the sides of a triangle be x

a = 3x

b = 5x

c. = 7x

perimeter =300cm

3x + 5x + 7x = 300cm ( add all the values)

15x = 300cm. (transport 15 to the right side )

x. = 300/15

x = 20cm

3 × 20 cm = 60cm

5 × 20 cm =100cm

7 × 20 cm = 140cm

(Thus the sides are 60 cm , 100 cm , 140 cm

Now ,

we have to find out the semi perimeter )

semi perimeter (s) = a+b+c

/2

= 60+100+140. 300

——————— = ——— = 150cm

2. 2

By using heron's formula

Area of a triangle= √s(s-a)(s-b)(s-c)cm

= √150(150-60)(150-100)(150-140)cm

=√150×90×50×10cm

= √3×5×10×3×3×10×10×5×10cm

= 1500√3cm²

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