Find the area of a triangle whose sides are in the ratio of 5:12:13 and its perimeter is 60 cm.
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Answered by
1
5x + 12x + 13x =60
30x = 60
X =3/6
X = 2
First side 10cm
Second side 24cm
Third side 26cm
Answered by
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Let the sides be 5x, 12x and 13x.
Perimeter = 60 cm (Given)
Also, Perimeter = Sum of all sides
•°• Sum of all sides = 60 cm
5x + 12x + 13x = 60
30x = 60
x = 60 / 30
x = 2
Sides are :
First side = 5x = 5 ( 2 ) = 10 cm
Second side = 12x = 12 ( 2 ) = 24 cm
Third side = 13x = 13 ( 2 ) = 26 cm
Applying Heron's Formula :
s = ( a + b + c ) / 2
Here, a, b and c are the sides of Triangle.
s = ( 10 + 24 + 26 ) / 2 = 60 / 2 = 30
Now,
Area of Triangle = √ s ( s - a ) ( s - b ) ( s - c )
= √ 30 ( 30 - 10 ) ( 30 - 24 ) ( 30 - 26 )
= √ 30 ( 20 ) ( 6 ) ( 4 )
= √ 2 × 2 × 2 × 2 × 3 × 3 × 10 × 10
= 10 × 2 × 2 × 3
= 120 cm²
Hence, the area of triangle is 120 cm².
Perimeter = 60 cm (Given)
Also, Perimeter = Sum of all sides
•°• Sum of all sides = 60 cm
5x + 12x + 13x = 60
30x = 60
x = 60 / 30
x = 2
Sides are :
First side = 5x = 5 ( 2 ) = 10 cm
Second side = 12x = 12 ( 2 ) = 24 cm
Third side = 13x = 13 ( 2 ) = 26 cm
Applying Heron's Formula :
s = ( a + b + c ) / 2
Here, a, b and c are the sides of Triangle.
s = ( 10 + 24 + 26 ) / 2 = 60 / 2 = 30
Now,
Area of Triangle = √ s ( s - a ) ( s - b ) ( s - c )
= √ 30 ( 30 - 10 ) ( 30 - 24 ) ( 30 - 26 )
= √ 30 ( 20 ) ( 6 ) ( 4 )
= √ 2 × 2 × 2 × 2 × 3 × 3 × 10 × 10
= 10 × 2 × 2 × 3
= 120 cm²
Hence, the area of triangle is 120 cm².
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