Math, asked by shivangigite7425, 1 year ago

Find the area of a triangle whose sides are measures 12cm 6cm 15cm

Answers

Answered by BrainlyKing5
35
\Large \underline{ \textbf{Given}}

To Find area of a triangle whose sides measures 12cm , 6cm and 15cm

\Large \underline{ \textbf{Solution}}

Let -

First Side ( a ) = 12cm

Second Side ( b ) = 6cm

Third Side ( c ) = 15cm

Now to find area of a triangle we have a formula known as \underline{\textbf{Heron's Formula }}

by this formula we have --

\boxed{\mathbf{Area \: of \: Triangle \: = \: \sqrt{s(s - a)(s - b)(s - c)}}}

Where

\mathbf{S\: =\: Semi-Perimeter\: = \:\dfrac{a + b + c}{2}}

\underline{\textbf{Step - 1 ) Form an equation with help of the above formula }}

Now by Putting Values of a = 12cm , b = 6cm , c = 15cm in this Formula We have \implies

\mathbf{Area \: of \: triangle \: = \sqrt{s(s - 12)(s - 6)(s - 15)}}

Now we know that

\sf{S\: = \: \dfrac{a+b+c}{2}}

That is

\sf{S\: = \: \dfrac{12cm + 6cm + 15cm}{2}\:=\:16.5 cm}

Now Putting value of ' S ' in the obtained formula we have \implies

\mathbf{Area \: of \: triangle \: = \sqrt{16.5(16.5 - 12)(16.5 - 6)(16.5 - 15)}}

\underline{\textbf{Step-2 ) Solve the obtained equation}}

\mathbf{Area \: of \: triangle \: = \sqrt{16.5(16.5 - 12)(16.5 - 6)(16.5 - 15)}}

\mathbf{\implies \:\sqrt{16.5(4.5)(10.5)(1.5)}}

\mathbf{\implies \:\sqrt{16.5(70.875)}}

\mathbf{\implies \:\sqrt{16.5(70.875)}}

\mathbf{\implies \:\sqrt{1,169.4375\:cm^4}}

That is

\mathbf{Area \: of \: triangle\: = \: 34.12\:cm^2 (Approx)}

\underline{\bf{Hence\: The\: Required \:Answer \:Is\: \implies}}

\boxed{\boxed{\mathbf{Area \: = \:34.12 \:cm^2}}}
Answered by Anonymous
6

ANSWER:-

Given:

A triangle whose sides are measures 12cm, 6cm & 15cm.

To find:

Find the area of a triangle.

Solution:

Using the Heron's Formula

⏺️A= 12cm

⏺️B= 6cm

⏺️C= 15cm

s =  \frac{A + B + C}{2}  \\  \\  =  >  \frac{12 + 6 + 15}{2}  \\  \\   =  >  \frac{33}{2}  \\  \\  =  > 16.5cm

Therefore,

Semi- perimeter= 16.5cm

Now,

We know that area of triangle is;

A(\triangle\:ABC) =  \sqrt{s(s - a)(s - b)(s - c)}  \\  \\  =  >  \sqrt{16.5(16.5 - 12)(16.5  - 6)(16.5 - 15)}  \\  \\  =  >  \sqrt{16.5(4.5)(10.5)(1.5)}  \\  \\  =  >  \sqrt{1169.43}  \\  \\  =  > 34.19 {cm}^{2}

Hence,

The area of triangle is 34.19cm².

Hope it helps ☺️

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