Find the area of a triangle whose sides are respectively 150 cm, 120 cm, and 200 cm.
Answers
Given : Sides of a triangle ∆ are 150 cm, 120 cm, and 200 cm.
Let the sides of the triangle are a = 150 cm, b = 120 cm & c = 200 cm.
Semi Perimeter of the ∆,s = (a + b + c) /2
s = (150 + 120 + 200) / 2
s = 470/2
s = 235 cm
Semi Perimeter of the ∆ = 235 cm
Using Heron’s formula :
Area of the wall , A = √s (s - a) (s - b) (s - c)
A = √235(235 – 150) (235 – 120) (235 – 200)
A = √235 × 85 × 115 × 35
A = √(47 × 5) × (17 × 5) × (23 × 5) × (5 × 7)
A = √(5 × 5 × 5 × 5) × 47 × 17 × 23 × 7
A = 25√47 × 17 × 23 × 7
A = 25 √128639
A = 25 × 358.663
A = 8966.56 cm²
Hence, the area of a triangle is 8966.56 cm².
HOPE THIS ANSWER WILL HELP YOU…..
Similar questions :
The triangular side walls of a flyover have been used for advertisements. The sides of the walls are 122m, 22m, and 120m (see the given figure). The advertisements yield an earning of Rs 5000 per m 2 per year. A company hired one of its walls for 3 months. How much rent did it pay?
https://brainly.in/question/1425893
A triangle has sides 35 cm, 54 cm and 61 cm long. Find its area. Also, find the smallest of its altitudes.
https://brainly.in/question/15908217
Answer:
Step-by-step explanation:
Given :-
Sides of a triangle triangle are 150 cm, 120 cm, and 200 cm.
To Find :-
Area of a triangle.
Formula to be used :-
Area of the triangle = √s (s - a) (s - b) (s - c)
Solution :-
Let the sides be a, b and c.
⇒ s = (a + b + c) /2
⇒ s = (150 + 120 + 200) / 2
⇒ s = 470/2
⇒ s = 235 cm
Area of the triangle = √s (s - a) (s - b) (s - c)
⇒ Area of the triangle = √235(235 - 150)(235 - 120)(235 - 200)
⇒ Area of the triangle = √235 × 85 × 115 × 35
⇒ Area of the triangle = √80399375
⇒ Area of the triangle = 8966.57 cm²
Hence, the area of a triangle is 8966.57 cm².