Question

Find the area of a triangle whose two of the sides are 13 cm
and 11 cm and the perimeter is 32 cm.

Answer 1

Answer:

= 8√30cm²

Step-by-step explanation:

let the sides of the triangle be a, b and c

given length of the sides of the triangle are :-

a = 8cm

b = 11cm

c = ?

perimeter of the triangle is given = 32cm

since the sum of all three sides of a triangle is it's perimeter

=> a + b + c = 32cm

=> 8 + 11 + c = 32cm

=> 19 + c = 32cm

=> c = 32 - 19

=> c = 13cm

now we will find the area of the triangle by heron's formula which is √s(s-a)(s-b)(s-c) where s is the semi-perimeter of the triangle.

semi-perimeter of this triangle = 32/2

= 16cm

area of the triangle = √16(16-8)(16-11)(16-13)

= √(16 × 8 × 5 × 3)

= √(2 × 2 × 2 × 2 × 2 × 2 × 2 × 5 × 3)

= 2 × 2 × 2√(2 × 5 × 3)

= 8√30cm²

Answer 2

Answer:

you have to use heron's formula.

hope you are aware of that, if not just answer any of my questions, I will explain in detail.

the third side is 8cm.

value of 's' will be half of perimeter, hence, 16.

now, formula is:

√s*(s-a)(s-b)(s-c)

apply values....

√16 x 3x5x8

44cm^2 will be answer.