find the area of a triangle whose two side are 8 and 11 and perimeter is 32
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Answer:
let the third angle be x
so, 8+11+x=32
19+x=32
x=32-19=13
so, the area of the triangle= 3×side
=8×11×13=1144
CHIKU2064:
sorry it is 1144 not 1244
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