Question

find the area of a triangle whose two sides are 18 cm and 10 cm and the perimeter is 42 CM ​

Answer 1

Answer:

the answer is 14

Step-by-step explanation:

first add the both sides 18+10=28

then subtract it from the corresponding perimeter 42-28=14

Answer 2

Step-by-step explanation:

v. Perimeter of triangle = 42 cm

a + b + c = 42 cm

18 + 10 + c = 42 cm

c = 42 - 28 = 14 cm

S = (a + b + c)/2 = 42/2 = 21 cm

Area of triangle

= √S(S-a)(S-b)(S-c)

= √21(21-18)(21-10)(21-14)

= √21 * 3 * 11 * 7

= √3*7*3*11*7

= 21√11 cm²