Question

Find the area of a triangle whose two sides are 18 cm and 10 cm and the perimeter is 42cm.

Answer 1

Hero's Formula:

√s ( s - a ) ( s - b ) ( s - c )

Given:

Side A (a) = 18 cm

Side B (b) = 10 cm

Perimeter = 42 cm

To Find:

The area of the triangle.

Solution:

Side C (c) = Perimeter - (Side A + Side B)

Side C (c) = 42 - 28

Side C (c) = 14 cm

Semi - Perimeter (s) = 42/2 = 21 cm

By putting the values of the sides, we get

√21 (21-18) (21-10) (21-14)

= √21 (3) (11) (7)

= √21 ( 231 )

= √4851

= 21√11 sq.cm

Answer 2

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Hero's Formula:

√s ( s - a ) ( s - b ) ( s - c )

Given:

Side A (a) = 18 cm

Side B (b) = 10 cm

Perimeter = 42 cm

To Find:

The area of the triangle.

Solution:

Side C (c) = Perimeter - (Side A + Side B)

Side C (c) = 42 - 28

Side C (c) = 14 cm

Semi - Perimeter (s) = 42/2 = 21 cm

By putting the values of the sides, we get

√21 (21-18) (21-10) (21-14)

= √21 (3) (11) (7)

= √21 ( 231 )

= √4851

= 21√11 sq.cm