Find the area of a triangle whose two sides are 20 cm and 50 cm and semi perimeter is 45 cm
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given=side 1 is equals to 20cm
side to equals to 50 CM
semi perimeter is equals to 45 CM
area of triangle-—
perimeter of triangle will be semi perimeter* 2
therefore perimeter of triangle will be 90 cm
90= S1+S2+S3
S3=20
AREA OF TRIANGLE= √S(s-a) (s-b) ( s-c)
√45 (45-50)( 45-20)(45-20)
√45*-5*25*25
3*3*5* -5*5*5*5*5
Making pairs
-125*9=√1125.
if you want you can solve this under root
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