Math, asked by taniya389, 3 months ago

Find the area of a triangle whose two sides are 8 cm and 11 cm and the perimeter is 32 cm​

Answers

Answered by gurnoor1103
2

Answer:

43.82cm²

a=side=8cm

b-base = 11 cm

p=perimiter =32cm

Step-by-step explanation:

Using the formulas

A=s(s﹣a)(s﹣b)(s﹣c)

P=a+b+c

s=a+b+c

2

Solving forA

A=1

4﹣P4+4P3a+4P3b﹣4(Pa)2﹣12P2ab﹣4(Pb)2+8Pa2b+8Pab2=1

4·﹣324+4·323·8+4·323·11﹣4·(32·8)2﹣12·322·8·11﹣4·(32·11)2+8·32·82·11+8·32·8·112≈43.8178cm²

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