Question

find the area of a triangle whose two sides are of lengths 36cm and 20cm and perimeter is 84cm.

Answer 1

3rd side =84-36+20
=28cm

a=36
b=20
c=28

s=a+b+c/2
=36+20+28/2
=84/2
=42

so area=√s(s-a)(s-b)(s-c)
=√42(42-36)(42-20)(42-28)
=√42.6.22.14
=√77616 cm^2

Answer 2

third side=84-(36+20)
=28
semi perimeter of triangle= 84/2
=42
area of triangle=√42(42-36)(42-20)(42-28)
=84cm^2