Question

Find the area of a triangle whose vertices (1,-1).(-4.0) and (-3.-5).​

Answer 1

The area of triangle is "12 square units".

Step-by-step explanation:

Here, $x_1 = 1, y_1 = - 1, x_2 = - 4, y_2 = 0$and $x_3 = - 3, y_3 =- 5$

We know that,

Area of triangle

= $\dfrac{1}{2}$ ×${x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)}$

∴ Area of triangle ABC

= $\dfrac{1}{2}$ × {1(0 + 5) - 4(- 5 + 1) - 3(- 1 - 0)}

= $\dfrac{1}{2}$ × {5 + 16 + 3}

= $\dfrac{1}{2}$ × 24

= 12 square units

Hence, the area of triangle is "12 square units".