Question

Find the area of a triangle whose vertices are (0, 3), (0, –3), (0, 7). pl answer it guys regards aditya

Answer 1

Step-by-step explanation:

height =7 units

base=6 units

area of triangle=1/2*b*h

=1/2*6*7

=42/2

=21 sq units

Answer 2

Answer:

let the three points be named as A(0,3), B(0,-3), C(0,7)

Now,

we have the formula to find are the of triangle:

so,

ar(∆ABC)=1/2(x1(y2-y3)+x2(y3-y1)+x3(y1-y2))

ar(∆ABC)=1/2(0(-3-7)+0(7-3)+0(3+3))

ar(∆ABC)=1/2(0)

ar(∆ABC)=0 sq. units

Because all the x-axis have the values zero which means these points are lying on the same plane...

so the area will be 0.

HOPE IT MAY HELP YOU