Question

find the area of a triangle whose vertices are (1,-1), (-4,6) and (-3,-5)​

Answer 1

Step-by-step explanation:

Did this in Google docs so i cropped it!

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Answer 2

Answer:

$\large\bf\underline{question}$

find the area of a triangle whose vertices are (1,-1), (-4,6) and (-3,-5)

$\large\bf\underline{given}$

vertices of the triangle= (1,-1),(-4,6) and(-3,-5)

$\large\bf\underline{to\:find}$

area of the triangle

$\large\bf\underline{solution}$

➔area of triangle= $\frac{1}{2} [ x_{1}(y2 - y3) + x_{2}(y3 - y1) + x_{3}(y1 - y2) ]$

➔$\frac{1}{2} [1(6 + 5) + ( - 4)( - 5 + 1) - 3( - 1 - 6)]$

➔$\frac{1}{2} [11 + 16 + 21 ] = \frac{48}{2} = 24$

$\tt\underline\red{area\:of\: triangle\:=\:24\:sq.\:units}$