Question

Find the area of a triangle whose vertices are (1, −1), (−4, 6) and (−3, −5).

Answer 1

Hi  Let,  x1= 1  x2= -4 x3 = -3 y1 = -1 y2= 6 y3 = -5  Now Area of Δ whose vertices are given = 1/2[x1(y2-y3) + x2(y3-y1) + x3(y1-y2)] Putting all the values we get,  1/2[1(6-(-5) + (-4(-5-(-1)) + (-3(-1-6)]  = 1/2 (11+16+21) =1/2(48) = 24 sq. Cm.   Hope it helps

Answer 2

"here is solution "

【hope it helps】