Question

Find the area of a triangle whose vertices are (1, 3),
(-2, 4) and (0, 6).​

Answer 1

Answer:

4

Step-by-step explanation:

• Area of triangle = 1/2 mod of [ x1 ( y2 - y3 ) + x2 ( y3 - y1 ) + x3 ( y1 - y2 ) ] .
• according to the given points x1 = 1 , x2 = -2 , x3 = 0 , y1 = 3 , y2 = 4 , y3 = 6
• 1/2 [ 1 ( 4 - 6 ) + (-2)(6 - 3) + 0 ( 3 - 4 ) ]
• 1/2 [ 1 ( -2 ) + (-2)(3) + 0(-1) ]
• 1/2 [ -2 -6 ]
• 1/2 [ -8 ]
• 1/2 ( 8)
• 4

Hope it helps you