Question

Find the area of a triangle whose vertices are (5,2), (4,7 ) and
(7,-4)​

Answer 1

here

x1=5 x2=4 x3=7

y1=2 y2=7 y3=-4

AREA= 1/3 |x1(y2-y3)+ x2(y3-y1)+ x3(y1-y2)|

:: 1/3 |5(7-(-4))+4(-4-2)+7(2-7)|

::1/3 |55+(-24)+(-35)|

::1/3|55-59|

::1/3×4

::4/3

::1.33

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