Question

Find the area of a triangle whose vertices are A (1, 2); B (3, 5) and C (-4,-7)​

Answer 1

Step-by-step explanation:

Plot the points in a rough diagram and take them in order.

Let the vertices be A(1,2),B(−3,4) and C(−5,−6)

Now the area of △ABC is

=

2

1

{(x

1

y

2

+x

2

y

3

+x

3

y

1

)−(x

2

y

1

+x

3

y

2

+x

1

y

3

)}

=

2

1

{(4+18−10)−(−6−20−6)}

=

2

1

(12+32)=22 sq.units.

Follo.w me