Question

find the area of a triangle whose vertices are a(-3, 6) b(5, 0) and c(-6, 2)​

Answer 1

Given:-

• a(-3, 6)
• b(5, 0)
• c(-6, 2)

To Find:-

• The Area Of Triangle

Solution:-

$area \: of \: triangle = \frac{1}{2}  [x _ 1 (y _ 2 – y_ 3 ) + x _ 2 (y _ 3 – y _ 1 ) + x _ 3(y _ 1 – y _ 2)]$

$= > A = \frac{1}{2} \times ( - 3(0 - 2) + 5(2 - 6) - 6(6 - 0))$

$= > A = \frac{1}{2} ( - 6 - 20 - 36)$

$= > A = - \frac{1}{2} \times 62$

$= > A = - 31$

We Know that Area Can not be In Negative

So,

$A = 31sq \: units$

Answer 2

Step-by-step explanation:

just refer to the above attachment

Hope it helps you