Question

Find the area of a triangle whose vertices are given as (1, –1) (–4, 6) and (–3, –5).

Answer 1

Answer

Area of triangle = 1/2 × [1(6 + 5) – 4(–5 + 1) – 3(–1 – 6)]

= 1/2 × [11 + 16 + 21]

= 48/2

= 24 sq. units

Answer 2

Explanation:

Area of triangle =1/2{1(6-(-5)+(-4)(-5-(-1)+(-3)(-1-6)}

=1/2{1×11+(-4×-4)+(-3×-7)

=1/2(11+16+21)

=1/2(48)

= 24 sq units