Question

Find the area of a triangle with base =18c.m and height =12c.m​

Answer 1

$\frac{1}{2} \times b \times h \\ \frac{1}{2} \times 18 \times 12 \\ = > 9 \times 12 \\ = > 108 \: cm {}^{2}$

Answer 2

Answer:

$\sf{108 {cm}^{2}}$

Step-by-step explanation:

$\sf{\underline{given}}:base(b) = 18cm \\ \sf{height(h) = 12cm}$

$\sf{ \underline{to \: find}: area \: of \: triangle}$

$\sf{ \underline{solution}}:$

$\sf{</strong><strong>A</strong><strong>rea \: of \: a \: triange = \frac{1}{2} \times base(b) \times height(h)}$

$\sf{ = \frac{1}{2} \times 18cm \times 12cm}$

$\sf{ = \frac{1}{2} \times 216{cm}^{2}}$

${\sf = \frac{216}{2} {cm}^{2}}$

$\sf{= 108 {cm}^{2}}$

$\bf \pink{\underline{</strong><strong>✌</strong><strong>B</strong><strong>e \: happy</strong><strong>✌</strong><strong>}}$