find the area of a triangle with base 5 cm and whose height is equal to that of a rectangle with base 5 cm and area 20 cm ^2(square)
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for triangle
let
base be b
area be a
height be h
therefore
a=?
h=?
b=5 cm
for rectangle
let
breadth be B
area be A
height (lenght) be L
therefore
B=5 cm
L=?
A= 20 cm^2
since
A=B*L
20=5*L
L=4 cm
&
L=h (given)
h=4 cm
In the triangle
a=?
b=5 cm
h=4 cm
since
a=0.5*b*h
area=0.5*5*4
=0.5*20
=10 cm^2
let
base be b
area be a
height be h
therefore
a=?
h=?
b=5 cm
for rectangle
let
breadth be B
area be A
height (lenght) be L
therefore
B=5 cm
L=?
A= 20 cm^2
since
A=B*L
20=5*L
L=4 cm
&
L=h (given)
h=4 cm
In the triangle
a=?
b=5 cm
h=4 cm
since
a=0.5*b*h
area=0.5*5*4
=0.5*20
=10 cm^2
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