find the area of a triangle with sides 25 CM 17 cm and 26 and also find the height of the triangle corresponding to the smallest side of the triangle
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Answer:
204 cm^2, 24cm
Step-by-step explanation:
A = \sqrt{s(s-a)(s-b)(s-c)}
s(s−a)(s−b)(s−c)
, s = (a+b+c) / 2
s = (25+26+17) / 2 = 34
A = \sqrt{34(34-25)(34-17)(34-26)}
34(34−25)(34−17)(34−26)
= 204 cm^2
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A = (bh)/2
204 = 17h / 2
17h = 408
h = 408 / 17
h = 24 cm
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