Find the area of a triangle with sides 3 cm, 3 cm and 5 cm
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area of triangle =1/2 base*height
base=5cm
height^2=3^2-2.5^2(pythagorus theorem)
=2.75
Height=5sqrt of 11
area=1/2 *5*5sqrt of 11
=12.5sqrt(11)cm^2
base=5cm
height^2=3^2-2.5^2(pythagorus theorem)
=2.75
Height=5sqrt of 11
area=1/2 *5*5sqrt of 11
=12.5sqrt(11)cm^2
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