Question

find the area of a triangle with sides 6cm , 8cm , and 10cm (use heron's formula)​

Answer 1

Answer:

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Answer 2

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Given :

a = 6 cm

b = 8 cm

c = 10 cm

Solution :

s = ᵃ⁺ᵇ⁺ᶜ⁄₂

s = ⁶⁺⁸⁺¹⁰⁄₂

s = ²⁴⁄₂

∴ s = 12 cm

$\sf{Ar.(∆) = \sqrt{s(s - a)(s - b)(s - c)} }$

$\sf{Ar.(∆) = \sqrt{12(12 - 6)(12 - 8)(12 - 10)} }$

$\sf{Ar.(∆) = \sqrt{12 \times 6 \times 4 \times 2} }$

$\sf{Ar.(∆) = 2 \times \sqrt{2 \times 6 \times 6 \times 2} }$

$\sf{Ar.(∆) = 2 \times 2 \times 6}$

$\sf{Ar.(∆) = 4 \times 6}$

$\sf{\bold{\underline{∴Ar.(∆) = 24 {cm}^{2} }}}$

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