Question

find the area of a triangle with vertices (3,0) (7,0) and (8,4)
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Answer 1

Answer:

AR(triangle)=1/2{x1(y2-y3)+x2(y3-y1)+x3(y1-y2)}

=1/2 {3(0-4)+7(4-0)+8(0-0)}

=1/2{3(-4)+7(4)+8(0)}

=1/2{-12+28+0}

= 1/2{16}

= 1/2(16)

= 8squnits

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