Question

Find the area of a triangle with vertices a(1,-1) b (-4,6) c (-3,5)

Answer 1

Answer:

hope it will help you:-)

Answer 2

Answer:

Area =

$\frac{1}{2} \times (1(6 - 5) - 4(5 + 1) - 3( - 1 - 6))$

$\frac{1}{2} \times (1 \times 1 - 4 \times 6 - 3 \times - 7)$

$\frac{1}{2} \times (1 - 24 + 21)$

$\frac{1}{2} \times - 2$

$- 1$

Since area cannot be negative

Therefore area is 1sq units