Math, asked by faiz1234321, 1 year ago

Find the area of a triangular field of sides 18m, 24m , and 30.also find the altitude corresponding to the shortest side

Answers

Answered by bastab19
6
HERE IS YOUR ANSWER:
GIVEN SIDES: 18m,24m,30m
Therefore using Herons formula,
s= (a +b+c )÷2
s=(18 +24+30)÷2
s=(72)÷2
s=36.
Therefore area:√(s-a)(s-b)(s-c)
√(36-18)(36-24)(36-30)
√18×12×6
√3×3×2×3×2×2×3×2
3×3×2×2
=36m square.
HOPE THIS WILL HELP YOU
MARK IT AS THE BRAINLLIEST.

bastab19: sorry this will be 36 not 38
bastab19: now its ok
Answered by aak5abhinav
2

HERE IS YOUR ANSWER:

GIVEN SIDES: 18m,24m,30m

Therefore using Herons formula,

s= (a +b+c )÷2

s=(18 +24+30)÷2

s=(72)÷2

s=36.

Therefore area:√(s-a)(s-b)(s-c)

√(36-18)(36-24)(36-30)

√18×12×6

√3×3×2×3×2×2×3×2

3×3×2×2

=36m square.

HOPE THIS WILL HELP YOU

MARK IT AS THE BRAINLLIEST.

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