Question

Find the area of a triangular field, two sides of which are 510m and 520m and the perimeter is 1560m. Also find the cost of the field at the rate of ₹21 per m^2.​

Answer 1

$\sqrt{s(s-a)(s-b)(s-c)}$Answer:

Step-by-step explanation:

perimeter of traingle=1560m

semi perimeter(s)=1560/2=780

perimeter=sum of all sides(Let's suppose a and b are two given sides)

1560=510+520+c   (Let's suppose c is the third side)

after solving c=530m,a=510m,b=520m

Now area of traingle=\sqrt{s(s-a)(s-b)(s-c)}

area=$\sqrt{780*(780-510)*(780-520)*(780-530)}$

area=117000m^2

Rate of field per square metre=Rs 21

Total Rate=Total area * rate of field per m^2=117000*21

Cost of field= Rs 2457000