Question

find the area of a triangular field whose sides are 17m,19m,32m. also find the altitude of the triangle corresponding to the smallest side

please answer this question​

Answer 1

Answer:

Area=2√3750 m²

Step-by-step explanation:given:-

Sides => a- 17m

b- 19m. c- 32m

Semi-perimeter,s= (a+b+c)/2

=(17+19+32+)/2 =68/2

s=34m

Area=√s(s-a)(s-b)(s-c)

=√34(34-17)(34-19)(34-32)

=√34×17×15×2

=√7×2×2×17×3×5×2

=2√7×17×3×5×2

Area=2√3750 m²