Question

Find the area of a triangular field whose sides are 50 m, 45 m, and 35 m. Also find the

length of the altitude of the shortest side of the triangle.​

Answer 1

Answer:

I'm solving wait please

Answer 2

Given :  Triangle sides are 50 m, 45 m, and 35 m

To Find : Area of triangle

and length of altitude on shortest side

Solution:

Triangle sides are 50 m, 45 m, and 35 m

a = 50

b = 45

c = 35

s = (a + b + c)/2  = ( 50 + 45 + 35)/2  = 65

Using Heron formula

Area of triangle = √s(s -a)(s-b)(s-c)

=  √65(65 -50)(65-45)(65-35)

=  √65(15)(20)(30)

= √5 * 13(5 * 3)(10 * 2)(10*3)

= 5 * 10 * 3 √26

= 150√26 m²

Area of triangle = (1/2) * base * height

=> (1/2) * 35 *  altitude  =   150√26

=>  altitude  =      300√26 /35

=> altitude  =     60√26 /7  m

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