find the area of a triangular field whose sides are 50m, 45m and 35m
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Answered by
10
this can be done using the Herons Formula-
Herons formula= a+b+c/2=s
50+45+35/2= 65
area=√s(s-a)(s-b)(s-c)
=√65×15×20×30
=764.85m2
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Herons formula= a+b+c/2=s
50+45+35/2= 65
area=√s(s-a)(s-b)(s-c)
=√65×15×20×30
=764.85m2
plz mark as brainliest
Answered by
9
Let the triangular field be ABC in which -AB=50m,BC=45m,AC=35m
So,a=50m,b=45m,and c=35m
Semi-perimeter of ∆ABC=a+b+c/2
=50+45+35/2=130/2=65
Area of the triangular field ABC
=√s(s-a)(s-b)(s-c)=√65(65-50)(65-45)(65-35)
=√65×15×20×30
=√585000
=764.852m^2
Thus,the area of the triangular field is 764.852m^2.
So,a=50m,b=45m,and c=35m
Semi-perimeter of ∆ABC=a+b+c/2
=50+45+35/2=130/2=65
Area of the triangular field ABC
=√s(s-a)(s-b)(s-c)=√65(65-50)(65-45)(65-35)
=√65×15×20×30
=√585000
=764.852m^2
Thus,the area of the triangular field is 764.852m^2.
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