find the area of a triangular field whose sides are 78m,50m and 112m
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we have to solve the question using heron's Formula
semi perimeter of Δ= perimeter/2
= 78+50+112/2
240/2
120m
formula=√s(s-a)(s-b)(s-c)
=√120(120-78)(120-50)(120-112)
= √120×42×70×8
= √6×2×10×7×6×7×10×2×2×2
= √6²×7²×10²×2²×2²
=√(6×7×10×4)²
=6×7×10×4
=2240m²
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