Find the area of AABC given that: (a) BC = 5 cm, CA = 7 cm, and ZBCA = 90°
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Answered by
0
Answer:
AC2=AB2+AC2
Given, AB=5 cm, BC=x
52=x2+32
x2=52−32=25−9=16
x=16=4 cm
Hence, AB=4 cm.
Answered by
3
Answer:
Step-by-step explanation:
if you want to know ,how I derive the following steps,refer the image given
angle BCA=90°
BC is the height=5cm
CA is the base=7cm
area of triangle=1/2×base×height.
=1/2×7×5 cm
=17.5 cm square
area of triangle ABC is 17.5 cm square
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