Question

Find the area of AABC given that ZABC = 90°,
AB= 4 cm, and BC = 5 cm.
10.

Answer 1

Answer:

angle ABC = 90

AB= height = 4cm

BC = base = 5cm

area of triangle =

$\\ area \: = \frac{1}{2} \times base \times height \\ = \frac{1}{2} \times 4 \times 5 \\ = 5 \times 2 \\ = 10 {cm}^{2}$

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