find the area of ∆ABC
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So ,area is 5√455 cm²....
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AnswEr :-
• The area of the triangle ABC is 5√455cm².
Given :-
• A ∆ ABC with sides as 12cm, 18cm and 20cm.
To Find :-
• Area of the ∆ ABC.
SoluTion :-
First we've to find the semi - perimeter of the triangle.
Here,
• a = 12
• b = 18
• c = 20
Formula for finding semi - perimeter (S)
» S = a + b + c / 2
→ S = 12 + 18 + 20 / 2
→ S = 50/2
→ S = 25
Formula for finding area of the triangle
» √s (s - a) (s - b) (s - c)
→ √ 25 (25 - 12) (25 - 18) (25 - 20)
→ √25 × 13 × 7 × 5
→ √ 5 × 5 × 13 × 7 × 5
→ 5√455cm²
Hence, the area of the triangle is 5√455cm².
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