Question

Find the area of ∆ABC, given that

1. AB=5cm,ABC=90°,BC=12cm
2.BC=7cm,BCA=90°,CA=11cm

plz help me
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Answer 1

Answer:

Area of right angle ∆ = 1/2 ×base×height

1 . height = 12 cm = BC , Base = 5cm ,where angle B = 90degre

Area of triangle = 12×5× 1/2 = 30 cm

2 . height = 11 cm = CA , Base =  7cm = BC ,where angle C = 90degre

Area of triangle = 1/2 × 7×11 = 77/2 cm

Answer 2

Step-by-step explanation:

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