find the area of ∆ abc given that
1 ab = 6 cm ,ac =7 cm ∆ bca = 50° ∆abc= 40°
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Answer:
ab=6cm,ac=7cm angle c=50 and angle b=40
the sum of ∆ is 180
a+b+c=180
a+40+50=180
a=180-90
a=90
area of ∆ = ½*base *height
=½*6*7
=½*42
=21cm²
Step-by-step explanation:
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