Question

Find the area of ∆ABC, given that angle ABC = angle CAB =45° ,AB=8 cm

Answer 1

Heya

Here goes the answer

Angle ABC = angle CAB = 45°

Angle A + B + C =180°

45+45+ angle C =180

Angle C = 90°

=> ∆ ABC is right angled at C and is an isosceles

It is isosceles because sides opposite to equal angles are equal

AC=BC=x

AB² = AC²+BC²

8² = x²+x²

64 = 2x²

64/2 = x²

√32 = 4√2 = x

AC = BC = 4√2

Area = 1/2 × 4√2 × 4√2

=4×4×2/2

=4×4

=16cm²

Answer 2

there you go .... Good question