Find the area of ABC where A(1,-4) and midpoints of the sides through A being (2,-1) and (0,-1)
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Triangle ABC has three points, A,B & C.
Coordinates of A is : .
Midpoint of AB is:
Midpoint of AC is:
We need to find the area of the triangle.
Let coordinates of point B be .
Mid point of AB is :
But since mid point of AB is
Thus,
Coordinates of point B is : .
Let Coordinate of point C be
Mid point of AC is :
But since mid point of AC is
Thus,
Coordinates of point C is : .
Area of a triangle whose vertices are is:
Area
In the given case, corresponds to B, corresponds to C, and corresponds to A.
Hence area of the triangle =
Hence, area of the triangle is sq.units.
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As the mid points from the point A are(2,-1) & (0,-1). From this we can find the point B and C by using mod point formula x1 + x2 /2 which are... B(3,2) and C(-1,2) . Then we will apply area formula..... We will get the answer as 12 Sq. Units
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