Question

Find the area of
ABC where AB = c, AC = b and BC = a.
b = c = 10 cm,
B = 32

Answer 1

Answer:

44,93970231

Step-by-step explanation:

AB = c, AC = b

b = c = 10 cm

=> isosceles triangle

C^=B^=32

=> A^=116

S= $\frac{1}{2}$ AH.BC

AH= Sin32 . AB = 10Sin32

BC=2BH=2($10^{2} -(10Sin32)^{2}$=16,9606192

S=1/2 (10Sin32) . 16,9606192 = 44,93970231