find the area of an equilateral triangle, each of whose side is 10 cm
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Solution :-
Area of an equilateral triangle = √3/4*a²
Where a = 10 cm (each side of the equilateral triangle)
⇒ √3/4*10*10
⇒ √3/4*100
⇒ (1.732*100)/4
⇒ 173.2/4
= 43.3 sq cm
So, the area of the given equilateral triangle is 43.3 sq cm
Answer.
Area of an equilateral triangle = √3/4*a²
Where a = 10 cm (each side of the equilateral triangle)
⇒ √3/4*10*10
⇒ √3/4*100
⇒ (1.732*100)/4
⇒ 173.2/4
= 43.3 sq cm
So, the area of the given equilateral triangle is 43.3 sq cm
Answer.
Answered by
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We have to find the area 'A' of an equilateral triangle whose side is given as 10 cm. Since in equilateral triangle, all the sides are equal so each side will be of length 10 cm
We know that the formula for the area of the triangle with side length 'a' is
Area = A = √3/2 a²
Substitute a = 10 cm, we get:
Area = A = √3/4 (10)²
Area = A = √3/4 (100)
Area = A = 43.3 cm²
This is the required answer.
Hopefully it is helpful. Thanks.
We know that the formula for the area of the triangle with side length 'a' is
Area = A = √3/2 a²
Substitute a = 10 cm, we get:
Area = A = √3/4 (10)²
Area = A = √3/4 (100)
Area = A = 43.3 cm²
This is the required answer.
Hopefully it is helpful. Thanks.
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