Find the area of an equilateral triangle having altitude h cm.
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Altitude of an equilateral triangle , bisects the base. If each side = a unit
By Pythagiras law, a² = (a/2)² + h²
=> a² - a²/4 = h²
=> h = √(3a²/4) = √3a/2
=> a = 2h/√3
Area( triangle) = 1/2 * a * h
=> area = 1/2 * 2h/√3 * h = h²/√3 = √3h² /3
Area = √3h² /3
hope its help you
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Altitude=h
Area of a triangle=(1/2)×base ×height
=(1/2)×(h/2)×b/2(If b is one side)
=hb/8
Area of a triangle=(1/2)×base ×height
=(1/2)×(h/2)×b/2(If b is one side)
=hb/8
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