Question

Find the area of an equilateral triangle having the length of side 10 cm?

Answer 1

As we know that the are of equilateral triangle is [tex]a^{2} \sqrt{3}/4 [/tex]

Here,

Side = 10

Now,

area of equilateral triangle = $10^{2} \sqrt{3}/4$

Area of equilateral triangle =$100 \sqrt{3}/4$

Area of equilateral triangle =$25 \sqrt{3}$ $cm^{2}$


I hope this will help you


-by ABHAY

Answer 2

Hey friend,
Here is the answer you were looking for:

As we know that for equilateral triangle,
we apply the formula:
$\frac{ \sqrt{3} }{4} (side)^{2} \\ \\ so \\ given \\ the \: side \: of \: triangle = 10cm \\ \\ area = \frac{ \sqrt{3} }{4} \times {(10)}^{2} \\ \\ = \frac{ \sqrt{3} }{4} \times 100 \\ \\ after \: cancelling \: we \: get \\ = \sqrt{3} \times 25 \\ \\ area = 25 \sqrt{3} {cm}^{2}$

Hope this helps!!!

@Mahak24

Thanks...
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