Question

Find the area of an equilateral triangle of sides 8 dm each​

Answer 1

Given :-

Side = 8cm

Area of equilateral triangle =

$\frac{ \sqrt{3} }{4} {(side)}^{2}$

$= \frac{ \sqrt{3} }{4} {(8)}^{2}$

$= \frac{ \sqrt{3} }{4} 64$

$= 16 \sqrt{3} {cm}^{2}$

Hence the area of equilateral triangle is 16√3 cm²

Answer 2

Answer:

16√3 is the area of that particular triangle

Step-by-step explanation:

suppose a triangle ∆ABC,

the triangle is equilateral than,

AB = BC = AC ..... {Given}

side = 8 cm

area of triangle = √3/4 × 8²

= √3/4 × 64

= √3 × 16

= 16√3 cm