Question

find the area of an equilateral triangle whose altitude is 5√3 cm​

Answer 1

Answer: 2.7063 cm² (approx)

Step-by-step explanation:

Let the sides of the equilateral triangle be a cm each .

Then we have altitude = $\frac{1}{2} * \sqrt{3} * a$

=> 5√3 = $\frac{1}{2} * \sqrt{3} * a$

=> a/2 = 5

=> a = 2.5 cm

So each side = 2.5 cm

∴ Area of an equilateral triangle = $\frac{\sqrt{3} }{4} a^2$

=> $\frac{\sqrt{3} * (2.5)^2}{4}$

=> 1.5625 * √3 ≈ 2.7063 cm²

Hope this helps you .

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