Question

find the area of an equilateral triangle whose each side is 12 CM​

Answer 1

A ≈ 62.35

$A = \frac{ \sqrt{3} }{4} a {}^{2} = \frac{ \sqrt{3} }{4} .12 {}^{2} ≈62.35383 </p><p></p><p>$

Answer 2

AREA OF AN EQUILATERAL TRIANAGLE=

$\sqrt{3} {a}^{2} \div 4$

SO

$\sqrt{3 \times 12 {}^{2} } \div 4$

$\sqrt{3 \times 144} \div 4$

$\sqrt{432 \div 4}$

SO THE FINAL ANSWER IS:5.19.

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