find the area of an equilateral triangle whose perimeter is 180
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Perimeter of triangle is given as 180cm.
Each side is of 60cm.
Therefore by Heron's Formula.
Area of Triangle =
![\sqrt{s(s - a)(s - b)(s - c)} \sqrt{s(s - a)(s - b)(s - c)}](https://tex.z-dn.net/?f=+%5Csqrt%7Bs%28s+-+a%29%28s+-+b%29%28s+-+c%29%7D+)
Here, s= (a+b+c)/2
60+60+60=180
180/2= 90
![\sqrt{90(90 - 60) (90 - 60) (90 - 60)} \sqrt{90(90 - 60) (90 - 60) (90 - 60)}](https://tex.z-dn.net/?f=+%5Csqrt%7B90%2890+-+60%29+%2890+-+60%29+%2890+-+60%29%7D+)
![\sqrt{90(30)(30)(30)} \sqrt{90(30)(30)(30)}](https://tex.z-dn.net/?f=+%5Csqrt%7B90%2830%29%2830%29%2830%29%7D+)
![30 \times 30 \times 30 \times 30 \times 30 30 \times 30 \times 30 \times 30 \times 30](https://tex.z-dn.net/?f=30+%5Ctimes+30+%5Ctimes+30+%5Ctimes+30+%5Ctimes+30)
![30 \times 30 \sqrt{30} 30 \times 30 \sqrt{30}](https://tex.z-dn.net/?f=30+%5Ctimes+30+%5Csqrt%7B30%7D+)
![900 \sqrt{30} 900 \sqrt{30}](https://tex.z-dn.net/?f=900+%5Csqrt%7B30%7D+)
Therefore, Area of triangle is 900√30 cm.
Hope it helps ✌✌☺☺
Each side is of 60cm.
Therefore by Heron's Formula.
Area of Triangle =
Here, s= (a+b+c)/2
60+60+60=180
180/2= 90
Therefore, Area of triangle is 900√30 cm.
Hope it helps ✌✌☺☺
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