Question

find the area of an equilateral triangle whose side is 8cm. Give the answer correct to two decimal places​

Answer 1

Answer:

.

$\sqrt{3 \div 4} \times {a}^{2}$

a^2=3/4 × 8^2

a^2=3/4×64

a^2=48

a (area)=sqrt (48).

Answer 2

Answer:

$\large\bold\red{Area=27.68\:{cm}^{2}}$

Step-by-step explanation:

Given,

An equilateral triangle

The length of the side of triangle is 8 cm.

Now,

we know that,

All sides of an equilateral triangle are Equal.

Therefore,

Area of an equilateral triangle is given by,

$\bold{\frac{ \sqrt{3} }{4} \times {(side)}^{2} }$

Therefore,

we get,

$Area = \frac{ \sqrt{3} }{4} \times {8}^{2} \\ \\ = \frac{ \sqrt{3} }{4} \times 64 \\ \\ = \sqrt{3 } \times 16 \\ \\ = 16 \sqrt{3}$

Hence,

$\bold{Area=16\sqrt{3}\:{cm}^{2}}$

Also,

Area in Correct to two decimal places is,

$\bold{Area=27.68\:{cm}^{2}}$