find the area of an equilateral triangle with side 2 √3cm.
Answers
Answered by
0
Step-by-step explanation:
Answer:
The area of the given equilateral triangle with side 2 \sqrt{3} \mathrm{cm}2
3
cm is 3 \sqrt{3} c m^{2}3
3
cm
2
Solution:
Equilateral triangle: The triangle which has equal sides. It is also known as equiangular i.e. all the internal angles are congruent to each other with 60^{\circ}60
∘
The triangle given is an equilateral triangle so, the three sides of the triangle are same which is a=2 \sqrt{3} \mathrm{cm}a=2
3
cm
\text { area of equilateral triangle } A=\frac{\sqrt{3}}{4} a^{2} area of equilateral triangle A=
4
3
a
2
\therefore A=\frac{\sqrt{3}}{4}(2 \sqrt{3})^{2}∴A=
4
3
(2
3
)
2
A=\frac{\sqrt{3}}{4} \times 2 \sqrt{3} \times 2 \sqrt{3}A=
4
3
×2
3
×2
3
A=\frac{4 \times 3 \times \sqrt{3}}{4}=3 \sqrt{3}A=
4
4×3×
3
=3
3
The area of the triangle is 3 \sqrt{3} c m^{2}3
3
cm
2
Answered by
1
Given that,
Side of an equalateral triangle = 2√3 cm
Area of triangle = ?
we know that,
- Area of an equalateral triangle = √3/4 × a²
- Area = √3/4 × (2√3)²
- Area = √3/4 × 4×3 cm²
- Area = 3√3 cm².
Therefore, the area of the equalateral triangle is 3√3 cm²
Hope this helps you.
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